Base | Representation |
---|---|
bin | 100101011111110010010… |
… | …1111000101011010110101 |
3 | 200020200002111201112222021 |
4 | 1022333210233011122311 |
5 | 1133413333323223432 |
6 | 14543253045433141 |
7 | 1041220421406253 |
oct | 112774457053265 |
9 | 20220074645867 |
10 | 5153503336117 |
11 | 1707652310a14 |
12 | 6b2949a0b7b1 |
13 | 2b4c863aa676 |
14 | 13b6065235d3 |
15 | 8e0c3b6b697 |
hex | 4afe4bc56b5 |
5153503336117 has 2 divisors, whose sum is σ = 5153503336118. Its totient is φ = 5153503336116.
The previous prime is 5153503336109. The next prime is 5153503336133. The reversal of 5153503336117 is 7116333053515.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5120802400561 + 32700935556 = 2262919^2 + 180834^2 .
It is a cyclic number.
It is not a de Polignac number, because 5153503336117 - 23 = 5153503336109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5153503336517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2576751668058 + 2576751668059.
It is an arithmetic number, because the mean of its divisors is an integer number (2576751668059).
Almost surely, 25153503336117 is an apocalyptic number.
It is an amenable number.
5153503336117 is a deficient number, since it is larger than the sum of its proper divisors (1).
5153503336117 is an equidigital number, since it uses as much as digits as its factorization.
5153503336117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 425250, while the sum is 43.
The spelling of 5153503336117 in words is "five trillion, one hundred fifty-three billion, five hundred three million, three hundred thirty-six thousand, one hundred seventeen".
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