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5153903 is a prime number
BaseRepresentation
bin10011101010010001101111
3100200211211022
4103222101233
52304411103
6302244355
761543646
oct23522157
910624738
105153903
112a00227
1218866bb
1310b5b61
1498235d
156bc138
hex4ea46f

5153903 has 2 divisors, whose sum is σ = 5153904. Its totient is φ = 5153902.

The previous prime is 5153899. The next prime is 5153917. The reversal of 5153903 is 3093515.

5153903 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5153903 - 22 = 5153899 is a prime.

It is a super-2 number, since 2×51539032 = 53125432266818, which contains 22 as substring.

It is equal to p358451 and since 5153903 and 358451 have the same sum of digits, it is a Honaker prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5153923) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2576951 + 2576952.

It is an arithmetic number, because the mean of its divisors is an integer number (2576952).

Almost surely, 25153903 is an apocalyptic number.

5153903 is a deficient number, since it is larger than the sum of its proper divisors (1).

5153903 is an equidigital number, since it uses as much as digits as its factorization.

5153903 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2025, while the sum is 26.

The square root of 5153903 is about 2270.2209143605. The cubic root of 5153903 is about 172.7343646295.

The spelling of 5153903 in words is "five million, one hundred fifty-three thousand, nine hundred three".