Base | Representation |
---|---|
bin | 10111011100010100010010… |
… | …10001010110010011100111 |
3 | 20202112011212000102021020202 |
4 | 23232022021101112103213 |
5 | 23224100411112403444 |
6 | 301345550100221115 |
7 | 13600254313344035 |
oct | 1356121121262347 |
9 | 222464760367222 |
10 | 51550500512999 |
11 | 15475498691334 |
12 | 59469ba39a79b |
13 | 229c2644b0a27 |
14 | ca30b3c51555 |
15 | 5e5e307b934e |
hex | 2ee2894564e7 |
51550500512999 has 2 divisors, whose sum is σ = 51550500513000. Its totient is φ = 51550500512998.
The previous prime is 51550500512941. The next prime is 51550500513047. The reversal of 51550500512999 is 99921500505515.
51550500512999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51550500512999 - 28 = 51550500512743 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51550500512299) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25775250256499 + 25775250256500.
It is an arithmetic number, because the mean of its divisors is an integer number (25775250256500).
Almost surely, 251550500512999 is an apocalyptic number.
51550500512999 is a deficient number, since it is larger than the sum of its proper divisors (1).
51550500512999 is an equidigital number, since it uses as much as digits as its factorization.
51550500512999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4556250, while the sum is 56.
The spelling of 51550500512999 in words is "fifty-one trillion, five hundred fifty billion, five hundred million, five hundred twelve thousand, nine hundred ninety-nine".
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