Base | Representation |
---|---|
bin | 110000000000101100… |
… | …000010100100111001 |
3 | 11221001200120212202021 |
4 | 300000230002210321 |
5 | 1321034043334231 |
6 | 35403212034441 |
7 | 3503325365035 |
oct | 600054024471 |
9 | 157050525667 |
10 | 51551152441 |
11 | 1a954310918 |
12 | 9ba8462a21 |
13 | 4b27231ac9 |
14 | 26d074b1c5 |
15 | 151ab45811 |
hex | c00b02939 |
51551152441 has 2 divisors, whose sum is σ = 51551152442. Its totient is φ = 51551152440.
The previous prime is 51551152417. The next prime is 51551152451. The reversal of 51551152441 is 14425115515.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 37179938041 + 14371214400 = 192821^2 + 119880^2 .
It is a cyclic number.
It is not a de Polignac number, because 51551152441 - 27 = 51551152313 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 51551152397 and 51551152406.
It is not a weakly prime, because it can be changed into another prime (51551152451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25775576220 + 25775576221.
It is an arithmetic number, because the mean of its divisors is an integer number (25775576221).
Almost surely, 251551152441 is an apocalyptic number.
It is an amenable number.
51551152441 is a deficient number, since it is larger than the sum of its proper divisors (1).
51551152441 is an equidigital number, since it uses as much as digits as its factorization.
51551152441 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20000, while the sum is 34.
Adding to 51551152441 its reverse (14425115515), we get a palindrome (65976267956).
The spelling of 51551152441 in words is "fifty-one billion, five hundred fifty-one million, one hundred fifty-two thousand, four hundred forty-one".
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