Base | Representation |
---|---|
bin | 100101100000100011111… |
… | …0101111001010101001101 |
3 | 200020211101101102222120102 |
4 | 1023001013311321111031 |
5 | 1133430240003102442 |
6 | 14544130043500445 |
7 | 1041306551363243 |
oct | 113010765712515 |
9 | 20224341388512 |
10 | 5155166065997 |
11 | 1708325938542 |
12 | 6b3132827725 |
13 | 2b518ca07abc |
14 | 13b7232a6793 |
15 | 8e16eb0c232 |
hex | 4b047d7954d |
5155166065997 has 2 divisors, whose sum is σ = 5155166065998. Its totient is φ = 5155166065996.
The previous prime is 5155166065993. The next prime is 5155166066021. The reversal of 5155166065997 is 7995606615515.
5155166065997 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3664242036841 + 1490924029156 = 1914221^2 + 1221034^2 .
It is a cyclic number.
It is not a de Polignac number, because 5155166065997 - 22 = 5155166065993 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5155166065993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2577583032998 + 2577583032999.
It is an arithmetic number, because the mean of its divisors is an integer number (2577583032999).
Almost surely, 25155166065997 is an apocalyptic number.
It is an amenable number.
5155166065997 is a deficient number, since it is larger than the sum of its proper divisors (1).
5155166065997 is an equidigital number, since it uses as much as digits as its factorization.
5155166065997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 76545000, while the sum is 65.
The spelling of 5155166065997 in words is "five trillion, one hundred fifty-five billion, one hundred sixty-six million, sixty-five thousand, nine hundred ninety-seven".
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