Base | Representation |
---|---|
bin | 1001100110100101… |
… | …01001011010100001 |
3 | 111022021222012121002 |
4 | 10303102221122201 |
5 | 41024301243122 |
6 | 2211324041345 |
7 | 241520654255 |
oct | 46322513241 |
9 | 14267865532 |
10 | 5155493537 |
11 | 2206161667 |
12 | bba693255 |
13 | 6421320bc |
14 | 36c9ba265 |
15 | 20291d992 |
hex | 1334a96a1 |
5155493537 has 2 divisors, whose sum is σ = 5155493538. Its totient is φ = 5155493536.
The previous prime is 5155493521. The next prime is 5155493543. The reversal of 5155493537 is 7353945515.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4214476561 + 941016976 = 64919^2 + 30676^2 .
It is a cyclic number.
It is not a de Polignac number, because 5155493537 - 24 = 5155493521 is a prime.
It is a super-2 number, since 2×51554935372 = 53158227220097540738, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5155493491 and 5155493500.
It is not a weakly prime, because it can be changed into another prime (5155493137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2577746768 + 2577746769.
It is an arithmetic number, because the mean of its divisors is an integer number (2577746769).
Almost surely, 25155493537 is an apocalyptic number.
It is an amenable number.
5155493537 is a deficient number, since it is larger than the sum of its proper divisors (1).
5155493537 is an equidigital number, since it uses as much as digits as its factorization.
5155493537 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1417500, while the sum is 47.
The square root of 5155493537 is about 71801.7655562870. The cubic root of 5155493537 is about 1727.5213188540.
The spelling of 5155493537 in words is "five billion, one hundred fifty-five million, four hundred ninety-three thousand, five hundred thirty-seven".
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