Base | Representation |
---|---|
bin | 100101100000101110011… |
… | …1101001100001011111011 |
3 | 200020212022001222220221211 |
4 | 1023001130331030023323 |
5 | 1133432001144043041 |
6 | 14544225140143551 |
7 | 1041321412332622 |
oct | 113013475141373 |
9 | 20225261886854 |
10 | 5155520299771 |
11 | 1708497894626 |
12 | 6b3211397bb7 |
13 | 2b521821409a |
14 | 13b7583566b9 |
15 | 8e190c80481 |
hex | 4b05cf4c2fb |
5155520299771 has 2 divisors, whose sum is σ = 5155520299772. Its totient is φ = 5155520299770.
The previous prime is 5155520299751. The next prime is 5155520299793. The reversal of 5155520299771 is 1779920255515.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5155520299771 is a prime.
It is a super-2 number, since 2×51555202997712 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5155520299751) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2577760149885 + 2577760149886.
It is an arithmetic number, because the mean of its divisors is an integer number (2577760149886).
Almost surely, 25155520299771 is an apocalyptic number.
5155520299771 is a deficient number, since it is larger than the sum of its proper divisors (1).
5155520299771 is an equidigital number, since it uses as much as digits as its factorization.
5155520299771 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9922500, while the sum is 58.
The spelling of 5155520299771 in words is "five trillion, one hundred fifty-five billion, five hundred twenty million, two hundred ninety-nine thousand, seven hundred seventy-one".
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