Base | Representation |
---|---|
bin | 100101100000101110011… |
… | …1101001100001100010001 |
3 | 200020212022001222220222122 |
4 | 1023001130331030030101 |
5 | 1133432001144043133 |
6 | 14544225140144025 |
7 | 1041321412332653 |
oct | 113013475141421 |
9 | 20225261886878 |
10 | 5155520299793 |
11 | 1708497894646 |
12 | 6b3211398015 |
13 | 2b52182140b6 |
14 | 13b7583566d3 |
15 | 8e190c80498 |
hex | 4b05cf4c311 |
5155520299793 has 2 divisors, whose sum is σ = 5155520299794. Its totient is φ = 5155520299792.
The previous prime is 5155520299771. The next prime is 5155520299807. The reversal of 5155520299793 is 3979920255515.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2989275018304 + 2166245281489 = 1728952^2 + 1471817^2 .
It is a cyclic number.
It is not a de Polignac number, because 5155520299793 - 212 = 5155520295697 is a prime.
It is a super-3 number, since 3×51555202997933 (a number of 39 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (5155520299703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2577760149896 + 2577760149897.
It is an arithmetic number, because the mean of its divisors is an integer number (2577760149897).
Almost surely, 25155520299793 is an apocalyptic number.
It is an amenable number.
5155520299793 is a deficient number, since it is larger than the sum of its proper divisors (1).
5155520299793 is an equidigital number, since it uses as much as digits as its factorization.
5155520299793 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 38272500, while the sum is 62.
The spelling of 5155520299793 in words is "five trillion, one hundred fifty-five billion, five hundred twenty million, two hundred ninety-nine thousand, seven hundred ninety-three".
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