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51594919433 is a prime number
BaseRepresentation
bin110000000011010010…
…111111111000001001
311221011201221110202222
4300003102333320021
51321131244410213
635411414103425
73504366402431
oct600322777011
9157151843688
1051594919433
111a976a94692
129bbb04ab75
134b33317135
1426d64a12c1
15151e8dd808
hexc034bfe09

51594919433 has 2 divisors, whose sum is σ = 51594919434. Its totient is φ = 51594919432.

The previous prime is 51594919373. The next prime is 51594919447. The reversal of 51594919433 is 33491949515.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50260259344 + 1334660089 = 224188^2 + 36533^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51594919433 is a prime.

It is a super-3 number, since 3×515949194333 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (51594919333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25797459716 + 25797459717.

It is an arithmetic number, because the mean of its divisors is an integer number (25797459717).

Almost surely, 251594919433 is an apocalyptic number.

It is an amenable number.

51594919433 is a deficient number, since it is larger than the sum of its proper divisors (1).

51594919433 is an equidigital number, since it uses as much as digits as its factorization.

51594919433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2624400, while the sum is 53.

The spelling of 51594919433 in words is "fifty-one billion, five hundred ninety-four million, nine hundred nineteen thousand, four hundred thirty-three".