Base | Representation |
---|---|
bin | 111010101011000010111001… |
… | …0100010111110010000010011 |
3 | 2111200022200011200222100002201 |
4 | 1311112011302202332100103 |
5 | 1020121102232134301141 |
6 | 5025344123131224031 |
7 | 213464143412233453 |
oct | 16526056242762023 |
9 | 2450280150870081 |
10 | 516089487025171 |
11 | 13a495360000794 |
12 | 49a71724ba8017 |
13 | 191c8050625567 |
14 | 9162c160a3d63 |
15 | 3e9ea12ac8031 |
hex | 1d561728be413 |
516089487025171 has 2 divisors, whose sum is σ = 516089487025172. Its totient is φ = 516089487025170.
The previous prime is 516089487025157. The next prime is 516089487025223. The reversal of 516089487025171 is 171520784980615.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 516089487025171 - 29 = 516089487024659 is a prime.
It is not a weakly prime, because it can be changed into another prime (516089487125171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 258044743512585 + 258044743512586.
It is an arithmetic number, because the mean of its divisors is an integer number (258044743512586).
Almost surely, 2516089487025171 is an apocalyptic number.
516089487025171 is a deficient number, since it is larger than the sum of its proper divisors (1).
516089487025171 is an equidigital number, since it uses as much as digits as its factorization.
516089487025171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 33868800, while the sum is 64.
The spelling of 516089487025171 in words is "five hundred sixteen trillion, eighty-nine billion, four hundred eighty-seven million, twenty-five thousand, one hundred seventy-one".
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