Base | Representation |
---|---|
bin | 1111000010111011110… |
… | …11101110000000001101 |
3 | 1211102101200001020012021 |
4 | 13201131323232000031 |
5 | 31432224313332113 |
6 | 1033254344210141 |
7 | 52231022410465 |
oct | 7413573560015 |
9 | 1742350036167 |
10 | 516972011533 |
11 | 18a27924aa0a |
12 | 84238a69951 |
13 | 3999a3c1953 |
14 | 1b0432d8ba5 |
15 | d6aab2c48d |
hex | 785deee00d |
516972011533 has 2 divisors, whose sum is σ = 516972011534. Its totient is φ = 516972011532.
The previous prime is 516972011509. The next prime is 516972011539. The reversal of 516972011533 is 335110279615.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 476780583049 + 40191428484 = 690493^2 + 200478^2 .
It is a cyclic number.
It is not a de Polignac number, because 516972011533 - 213 = 516972003341 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 516972011533.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (516972011539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 258486005766 + 258486005767.
It is an arithmetic number, because the mean of its divisors is an integer number (258486005767).
Almost surely, 2516972011533 is an apocalyptic number.
It is an amenable number.
516972011533 is a deficient number, since it is larger than the sum of its proper divisors (1).
516972011533 is an equidigital number, since it uses as much as digits as its factorization.
516972011533 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 170100, while the sum is 43.
The spelling of 516972011533 in words is "five hundred sixteen billion, nine hundred seventy-two million, eleven thousand, five hundred thirty-three".
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