Base | Representation |
---|---|
bin | 1001101000010010… |
… | …10011000101000101 |
3 | 111100021221001202211 |
4 | 10310021103011011 |
5 | 41041433214343 |
6 | 2212555103421 |
7 | 242053513303 |
oct | 46411230505 |
9 | 14307831684 |
10 | 5169819973 |
11 | 221325729a |
12 | 1003441b71 |
13 | 6450a9c96 |
14 | 370869273 |
15 | 203ced79d |
hex | 134253145 |
5169819973 has 2 divisors, whose sum is σ = 5169819974. Its totient is φ = 5169819972.
The previous prime is 5169819913. The next prime is 5169819983. The reversal of 5169819973 is 3799189615.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5152655524 + 17164449 = 71782^2 + 4143^2 .
It is a cyclic number.
It is not a de Polignac number, because 5169819973 - 29 = 5169819461 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5169819913) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2584909986 + 2584909987.
It is an arithmetic number, because the mean of its divisors is an integer number (2584909987).
Almost surely, 25169819973 is an apocalyptic number.
It is an amenable number.
5169819973 is a deficient number, since it is larger than the sum of its proper divisors (1).
5169819973 is an equidigital number, since it uses as much as digits as its factorization.
5169819973 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3674160, while the sum is 58.
The square root of 5169819973 is about 71901.4601590260. The cubic root of 5169819973 is about 1729.1200234733.
The spelling of 5169819973 in words is "five billion, one hundred sixty-nine million, eight hundred nineteen thousand, nine hundred seventy-three".
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