Base | Representation |
---|---|
bin | 110000001110011100… |
… | …101101100110101111 |
3 | 11221122202222221012111 |
4 | 300032130231212233 |
5 | 1322022143443112 |
6 | 35442140144451 |
7 | 3512130603643 |
oct | 601634554657 |
9 | 157582887174 |
10 | 51782015407 |
11 | 1aa62663661 |
12 | a051838127 |
13 | 4b63003b05 |
14 | 2713284c23 |
15 | 15310495a7 |
hex | c0e72d9af |
51782015407 has 2 divisors, whose sum is σ = 51782015408. Its totient is φ = 51782015406.
The previous prime is 51782015387. The next prime is 51782015429. The reversal of 51782015407 is 70451028715.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51782015407 - 27 = 51782015279 is a prime.
It is a super-3 number, since 3×517820154073 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 51782015407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51782015477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25891007703 + 25891007704.
It is an arithmetic number, because the mean of its divisors is an integer number (25891007704).
Almost surely, 251782015407 is an apocalyptic number.
51782015407 is a deficient number, since it is larger than the sum of its proper divisors (1).
51782015407 is an equidigital number, since it uses as much as digits as its factorization.
51782015407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 78400, while the sum is 40.
The spelling of 51782015407 in words is "fifty-one billion, seven hundred eighty-two million, fifteen thousand, four hundred seven".
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