Base | Representation |
---|---|
bin | 100101101101111001001… |
… | …1011101110010000000100 |
3 | 200100120021210022111021202 |
4 | 1023123302123232100010 |
5 | 1134412404231200310 |
6 | 15005223123402032 |
7 | 1043342226145520 |
oct | 113336233562004 |
9 | 20316253274252 |
10 | 5183797912580 |
11 | 1719488864671 |
12 | 6b87a3523318 |
13 | 2b7aa37c1a61 |
14 | 13cc7bb2cd80 |
15 | 8ec985823a5 |
hex | 4b6f26ee404 |
5183797912580 has 24 divisors (see below), whose sum is σ = 12441114990528. Its totient is φ = 1777302141408.
The previous prime is 5183797912567. The next prime is 5183797912583. The reversal of 5183797912580 is 852197973815.
It is a super-3 number, since 3×51837979125803 (a number of 39 digits) contains 333 as substring.
It is a Smith number, since the sum of its digits (65) coincides with the sum of the digits of its prime factors.
It is not an unprimeable number, because it can be changed into a prime (5183797912583) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18513563834 + ... + 18513564113.
It is an arithmetic number, because the mean of its divisors is an integer number (518379791272).
Almost surely, 25183797912580 is an apocalyptic number.
It is an amenable number.
5183797912580 is an abundant number, since it is smaller than the sum of its proper divisors (7257317077948).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5183797912580 is a wasteful number, since it uses less digits than its factorization.
5183797912580 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37027127963 (or 37027127961 counting only the distinct ones).
The product of its (nonzero) digits is 38102400, while the sum is 65.
The spelling of 5183797912580 in words is "five trillion, one hundred eighty-three billion, seven hundred ninety-seven million, nine hundred twelve thousand, five hundred eighty".
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