Base | Representation |
---|---|
bin | 10111100101000001000110… |
… | …10101100110010101011001 |
3 | 20210120202110111011012002122 |
4 | 23302200203111212111121 |
5 | 23244000122120440123 |
6 | 302135145241311025 |
7 | 13630666260522362 |
oct | 1362404325462531 |
9 | 223522414135078 |
10 | 51849438061913 |
11 | 1558025008a388 |
12 | 5994927a95475 |
13 | 22c14c517794b |
14 | cb3751c2ab69 |
15 | 5edac9a5cbc8 |
hex | 2f2823566559 |
51849438061913 has 2 divisors, whose sum is σ = 51849438061914. Its totient is φ = 51849438061912.
The previous prime is 51849438061901. The next prime is 51849438061987. The reversal of 51849438061913 is 31916083494815.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 27271759284169 + 24577678777744 = 5222237^2 + 4957588^2 .
It is a cyclic number.
It is not a de Polignac number, because 51849438061913 - 220 = 51849437013337 is a prime.
It is not a weakly prime, because it can be changed into another prime (51849438061513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25924719030956 + 25924719030957.
It is an arithmetic number, because the mean of its divisors is an integer number (25924719030957).
Almost surely, 251849438061913 is an apocalyptic number.
It is an amenable number.
51849438061913 is a deficient number, since it is larger than the sum of its proper divisors (1).
51849438061913 is an equidigital number, since it uses as much as digits as its factorization.
51849438061913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22394880, while the sum is 62.
The spelling of 51849438061913 in words is "fifty-one trillion, eight hundred forty-nine billion, four hundred thirty-eight million, sixty-one thousand, nine hundred thirteen".
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