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51849438061913 is a prime number
BaseRepresentation
bin10111100101000001000110…
…10101100110010101011001
320210120202110111011012002122
423302200203111212111121
523244000122120440123
6302135145241311025
713630666260522362
oct1362404325462531
9223522414135078
1051849438061913
111558025008a388
125994927a95475
1322c14c517794b
14cb3751c2ab69
155edac9a5cbc8
hex2f2823566559

51849438061913 has 2 divisors, whose sum is σ = 51849438061914. Its totient is φ = 51849438061912.

The previous prime is 51849438061901. The next prime is 51849438061987. The reversal of 51849438061913 is 31916083494815.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 27271759284169 + 24577678777744 = 5222237^2 + 4957588^2 .

It is a cyclic number.

It is not a de Polignac number, because 51849438061913 - 220 = 51849437013337 is a prime.

It is not a weakly prime, because it can be changed into another prime (51849438061513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25924719030956 + 25924719030957.

It is an arithmetic number, because the mean of its divisors is an integer number (25924719030957).

Almost surely, 251849438061913 is an apocalyptic number.

It is an amenable number.

51849438061913 is a deficient number, since it is larger than the sum of its proper divisors (1).

51849438061913 is an equidigital number, since it uses as much as digits as its factorization.

51849438061913 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 22394880, while the sum is 62.

The spelling of 51849438061913 in words is "fifty-one trillion, eight hundred forty-nine billion, four hundred thirty-eight million, sixty-one thousand, nine hundred thirteen".