Base | Representation |
---|---|
bin | 100101110000000101100… |
… | …0111100010101111010001 |
3 | 200101000102222022221120121 |
4 | 1023200023013202233101 |
5 | 1140002030244121431 |
6 | 15011322304110241 |
7 | 1043600016665416 |
oct | 113401307425721 |
9 | 20330388287517 |
10 | 5188507020241 |
11 | 1720484a48986 |
12 | 6b9698605381 |
13 | 2b83742c11ac |
14 | 13d1a730c10d |
15 | 8ee71bc8611 |
hex | 4b80b1e2bd1 |
5188507020241 has 2 divisors, whose sum is σ = 5188507020242. Its totient is φ = 5188507020240.
The previous prime is 5188507020239. The next prime is 5188507020247. The reversal of 5188507020241 is 1420207058815.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4490161000000 + 698346020241 = 2119000^2 + 835671^2 .
It is a cyclic number.
It is not a de Polignac number, because 5188507020241 - 21 = 5188507020239 is a prime.
Together with 5188507020239, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (5188507020247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2594253510120 + 2594253510121.
It is an arithmetic number, because the mean of its divisors is an integer number (2594253510121).
Almost surely, 25188507020241 is an apocalyptic number.
It is an amenable number.
5188507020241 is a deficient number, since it is larger than the sum of its proper divisors (1).
5188507020241 is an equidigital number, since it uses as much as digits as its factorization.
5188507020241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 179200, while the sum is 43.
The spelling of 5188507020241 in words is "five trillion, one hundred eighty-eight billion, five hundred seven million, twenty thousand, two hundred forty-one".
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