Base | Representation |
---|---|
bin | 100101110001100101000… |
… | …1100011001001011011111 |
3 | 200101022201101110101110101 |
4 | 1023203022030121023133 |
5 | 1140030111430140223 |
6 | 15013012341521531 |
7 | 1044042324110353 |
oct | 113431214311337 |
9 | 20338641411411 |
10 | 5191712740063 |
11 | 172187a548703 |
12 | 6ba2321132a7 |
13 | 2b87654b3325 |
14 | 13d3ccd85463 |
15 | 900ad3564ad |
hex | 4b8ca3192df |
5191712740063 has 2 divisors, whose sum is σ = 5191712740064. Its totient is φ = 5191712740062.
The previous prime is 5191712740001. The next prime is 5191712740073. The reversal of 5191712740063 is 3600472171915.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5191712740063 - 213 = 5191712731871 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5191712739995 and 5191712740022.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5191712740073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2595856370031 + 2595856370032.
It is an arithmetic number, because the mean of its divisors is an integer number (2595856370032).
Almost surely, 25191712740063 is an apocalyptic number.
5191712740063 is a deficient number, since it is larger than the sum of its proper divisors (1).
5191712740063 is an equidigital number, since it uses as much as digits as its factorization.
5191712740063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 317520, while the sum is 46.
The spelling of 5191712740063 in words is "five trillion, one hundred ninety-one billion, seven hundred twelve million, seven hundred forty thousand, sixty-three".
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