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5192631711413 is a prime number
BaseRepresentation
bin100101110010000000011…
…1101111111011010110101
3200101102002102122222011022
41023210000331333122311
51140034002204231123
615013243450350525
71044104153202206
oct113440075773265
920342072588138
105192631711413
111722201258463
126ba449a2b445
132b88809bcb63
1413d47903d5ad
1590113d7e1c8
hex4b900f7f6b5

5192631711413 has 2 divisors, whose sum is σ = 5192631711414. Its totient is φ = 5192631711412.

The previous prime is 5192631711353. The next prime is 5192631711431. The reversal of 5192631711413 is 3141171362915.

Together with next prime (5192631711431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3349276990609 + 1843354720804 = 1830103^2 + 1357702^2 .

It is a cyclic number.

It is not a de Polignac number, because 5192631711413 - 226 = 5192564602549 is a prime.

It is a super-3 number, since 3×51926317114133 (a number of 39 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5192631711713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2596315855706 + 2596315855707.

It is an arithmetic number, because the mean of its divisors is an integer number (2596315855707).

Almost surely, 25192631711413 is an apocalyptic number.

It is an amenable number.

5192631711413 is a deficient number, since it is larger than the sum of its proper divisors (1).

5192631711413 is an equidigital number, since it uses as much as digits as its factorization.

5192631711413 is an evil number, because the sum of its binary digits is even.

The product of its digits is 136080, while the sum is 44.

The spelling of 5192631711413 in words is "five trillion, one hundred ninety-two billion, six hundred thirty-one million, seven hundred eleven thousand, four hundred thirteen".