Base | Representation |
---|---|
bin | 10111100111010000101111… |
… | …10010001101011111101011 |
3 | 20210212010111210201210210201 |
4 | 23303220113302031133223 |
5 | 23301231040213201313 |
6 | 302234421320053031 |
7 | 13636366256264323 |
oct | 1363502762153753 |
9 | 223763453653721 |
10 | 51926553647083 |
11 | 155aaa228a1955 |
12 | 59a7869904177 |
13 | 22c886483780b |
14 | cb738988a283 |
15 | 600adebba0dd |
hex | 2f3a17c8d7eb |
51926553647083 has 2 divisors, whose sum is σ = 51926553647084. Its totient is φ = 51926553647082.
The previous prime is 51926553647069. The next prime is 51926553647113. The reversal of 51926553647083 is 38074635562915.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51926553647083 is a prime.
It is not a weakly prime, because it can be changed into another prime (51926553647483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25963276823541 + 25963276823542.
It is an arithmetic number, because the mean of its divisors is an integer number (25963276823542).
It is a 2-persistent number, because it is pandigital, and so is 2⋅51926553647083 = 103853107294166, but 3⋅51926553647083 = 155779660941249 is not.
Almost surely, 251926553647083 is an apocalyptic number.
51926553647083 is a deficient number, since it is larger than the sum of its proper divisors (1).
51926553647083 is an equidigital number, since it uses as much as digits as its factorization.
51926553647083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 163296000, while the sum is 64.
The spelling of 51926553647083 in words is "fifty-one trillion, nine hundred twenty-six billion, five hundred fifty-three million, six hundred forty-seven thousand, eighty-three".
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