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51934612365127 is a prime number
BaseRepresentation
bin10111100111011111110000…
…00111110001111101000111
320210212220022102122002201101
423303233320013301331013
523301344041231141002
6302242233114240531
713640103052252162
oct1363577007617507
9223786272562641
1051934612365127
1115603388825008
1259a9338726147
1322c954a29922b
14cb7911c7aad9
15600e12413587
hex2f3bf81f1f47

51934612365127 has 2 divisors, whose sum is σ = 51934612365128. Its totient is φ = 51934612365126.

The previous prime is 51934612365109. The next prime is 51934612365149. The reversal of 51934612365127 is 72156321643915.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 51934612365127 - 227 = 51934478147399 is a prime.

It is a super-2 number, since 2×519346123651272 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51934612366127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25967306182563 + 25967306182564.

It is an arithmetic number, because the mean of its divisors is an integer number (25967306182564).

Almost surely, 251934612365127 is an apocalyptic number.

51934612365127 is a deficient number, since it is larger than the sum of its proper divisors (1).

51934612365127 is an equidigital number, since it uses as much as digits as its factorization.

51934612365127 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8164800, while the sum is 55.

The spelling of 51934612365127 in words is "fifty-one trillion, nine hundred thirty-four billion, six hundred twelve million, three hundred sixty-five thousand, one hundred twenty-seven".