Base | Representation |
---|---|
bin | 110000011001111011… |
… | …111011001111111011 |
3 | 11222011012122201102111 |
4 | 300121323323033323 |
5 | 1322421013402011 |
6 | 35513223113151 |
7 | 3516661030006 |
oct | 603173731773 |
9 | 158135581374 |
10 | 51974747131 |
11 | 2005143187a |
12 | a0a62a27b7 |
13 | 4b93c14a58 |
14 | 2730ad453d |
15 | 1542e1a121 |
hex | c19efb3fb |
51974747131 has 2 divisors, whose sum is σ = 51974747132. Its totient is φ = 51974747130.
The previous prime is 51974747129. The next prime is 51974747183. The reversal of 51974747131 is 13174747915.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51974747131 - 21 = 51974747129 is a prime.
It is a super-3 number, since 3×519747471313 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 51974747129, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (51974748131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25987373565 + 25987373566.
It is an arithmetic number, because the mean of its divisors is an integer number (25987373566).
Almost surely, 251974747131 is an apocalyptic number.
51974747131 is a deficient number, since it is larger than the sum of its proper divisors (1).
51974747131 is an equidigital number, since it uses as much as digits as its factorization.
51974747131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 740880, while the sum is 49.
The spelling of 51974747131 in words is "fifty-one billion, nine hundred seventy-four million, seven hundred forty-seven thousand, one hundred thirty-one".
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