Base | Representation |
---|---|
bin | 111011001000101000001101… |
… | …0101001101000001110101111 |
3 | 2112012201100212102201010211211 |
4 | 1312101100122221220032233 |
5 | 1021134211122134414041 |
6 | 5042140022312255251 |
7 | 214363661245565314 |
oct | 16621203251501657 |
9 | 2465640772633754 |
10 | 520155346404271 |
11 | 140812709694686 |
12 | 4a4097110a1527 |
13 | 19431591a800a6 |
14 | 926392013cd0b |
15 | 402067a8e3481 |
hex | 1d9141aa683af |
520155346404271 has 2 divisors, whose sum is σ = 520155346404272. Its totient is φ = 520155346404270.
The previous prime is 520155346404217. The next prime is 520155346404299. The reversal of 520155346404271 is 172404643551025.
Together with previous prime (520155346404217) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-520155346404271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (520155346404371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 260077673202135 + 260077673202136.
It is an arithmetic number, because the mean of its divisors is an integer number (260077673202136).
Almost surely, 2520155346404271 is an apocalyptic number.
520155346404271 is a deficient number, since it is larger than the sum of its proper divisors (1).
520155346404271 is an equidigital number, since it uses as much as digits as its factorization.
520155346404271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032000, while the sum is 49.
Adding to 520155346404271 its reverse (172404643551025), we get a palindrome (692559989955296).
The spelling of 520155346404271 in words is "five hundred twenty trillion, one hundred fifty-five billion, three hundred forty-six million, four hundred four thousand, two hundred seventy-one".
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