Base | Representation |
---|---|
bin | 1001101100000101… |
… | …01110101011010001 |
3 | 111102111211022200211 |
4 | 10312002232223101 |
5 | 41123110334213 |
6 | 2220053244121 |
7 | 242621213305 |
oct | 46602565321 |
9 | 14374738624 |
10 | 5201652433 |
11 | 222a21950a |
12 | 1012033641 |
13 | 64b874063 |
14 | 374b93d05 |
15 | 2069da53d |
hex | 1360aead1 |
5201652433 has 2 divisors, whose sum is σ = 5201652434. Its totient is φ = 5201652432.
The previous prime is 5201652427. The next prime is 5201652461. The reversal of 5201652433 is 3342561025.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5133292609 + 68359824 = 71647^2 + 8268^2 .
It is a cyclic number.
It is not a de Polignac number, because 5201652433 - 29 = 5201651921 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5201652395 and 5201652404.
It is not a weakly prime, because it can be changed into another prime (5201652473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2600826216 + 2600826217.
It is an arithmetic number, because the mean of its divisors is an integer number (2600826217).
Almost surely, 25201652433 is an apocalyptic number.
It is an amenable number.
5201652433 is a deficient number, since it is larger than the sum of its proper divisors (1).
5201652433 is an equidigital number, since it uses as much as digits as its factorization.
5201652433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 31.
The square root of 5201652433 is about 72122.4821605580. The cubic root of 5201652433 is about 1732.6617043342.
The spelling of 5201652433 in words is "five billion, two hundred one million, six hundred fifty-two thousand, four hundred thirty-three".
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