Base | Representation |
---|---|
bin | 110000011111000010… |
… | …101010001110011101 |
3 | 11222101011211021000011 |
4 | 300133002222032131 |
5 | 1323104430222433 |
6 | 35525523003221 |
7 | 3522051041305 |
oct | 603702521635 |
9 | 158334737004 |
10 | 52060398493 |
11 | 20095812a24 |
12 | a10ab09511 |
13 | 4ba88a352c |
14 | 273c22c605 |
15 | 154a6d83cd |
hex | c1f0aa39d |
52060398493 has 2 divisors, whose sum is σ = 52060398494. Its totient is φ = 52060398492.
The previous prime is 52060398469. The next prime is 52060398503. The reversal of 52060398493 is 39489306025.
52060398493 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 50589906084 + 1470492409 = 224922^2 + 38347^2 .
It is a cyclic number.
It is not a de Polignac number, because 52060398493 - 25 = 52060398461 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52060390493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26030199246 + 26030199247.
It is an arithmetic number, because the mean of its divisors is an integer number (26030199247).
Almost surely, 252060398493 is an apocalyptic number.
It is an amenable number.
52060398493 is a deficient number, since it is larger than the sum of its proper divisors (1).
52060398493 is an equidigital number, since it uses as much as digits as its factorization.
52060398493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1399680, while the sum is 49.
The spelling of 52060398493 in words is "fifty-two billion, sixty million, three hundred ninety-eight thousand, four hundred ninety-three".
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