Base | Representation |
---|---|
bin | 110000011111101100… |
… | …110000111101100011 |
3 | 11222101221121000210120 |
4 | 300133230300331203 |
5 | 1323120241424011 |
6 | 35530555331323 |
7 | 3522243622101 |
oct | 603754607543 |
9 | 158357530716 |
10 | 52071436131 |
11 | 200a0a71740 |
12 | a112750b43 |
13 | 4baac69490 |
14 | 273d8a2c71 |
15 | 154b668a06 |
hex | c1fb30f63 |
52071436131 has 64 divisors (see below), whose sum is σ = 83215641600. Its totient is φ = 28543357440.
The previous prime is 52071436129. The next prime is 52071436199. The reversal of 52071436131 is 13163417025.
It is not a de Polignac number, because 52071436131 - 21 = 52071436129 is a prime.
It is a super-2 number, since 2×520714361312 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a junction number, because it is equal to n+sod(n) for n = 52071436092 and 52071436101.
It is not an unprimeable number, because it can be changed into a prime (52071436111) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 31808245 + ... + 31809881.
It is an arithmetic number, because the mean of its divisors is an integer number (1300244400).
Almost surely, 252071436131 is an apocalyptic number.
52071436131 is a deficient number, since it is larger than the sum of its proper divisors (31144205469).
52071436131 is a wasteful number, since it uses less digits than its factorization.
52071436131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3116.
The product of its (nonzero) digits is 15120, while the sum is 33.
The spelling of 52071436131 in words is "fifty-two billion, seventy-one million, four hundred thirty-six thousand, one hundred thirty-one".
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