Base | Representation |
---|---|
bin | 100101111010000111000… |
… | …0001110001000110111101 |
3 | 200110001222222212212100120 |
4 | 1023310032001301012331 |
5 | 1140330120323034430 |
6 | 15025242142445153 |
7 | 1045261263015546 |
oct | 113641601610675 |
9 | 20401888785316 |
10 | 5210030674365 |
11 | 172961a543890 |
12 | 7018a48937b9 |
13 | 2ba3c45507ca |
14 | 140249ad34cd |
15 | 907d15b2610 |
hex | 4bd0e0711bd |
5210030674365 has 64 divisors (see below), whose sum is σ = 9326853043200. Its totient is φ = 2461629864960.
The previous prime is 5210030674363. The next prime is 5210030674393. The reversal of 5210030674365 is 5634760300125.
It is not a de Polignac number, because 5210030674365 - 21 = 5210030674363 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5210030674363) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2224186 + ... + 3920084.
It is an arithmetic number, because the mean of its divisors is an integer number (145732078800).
Almost surely, 25210030674365 is an apocalyptic number.
5210030674365 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
5210030674365 is a deficient number, since it is larger than the sum of its proper divisors (4116822368835).
5210030674365 is a wasteful number, since it uses less digits than its factorization.
5210030674365 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1696394.
The product of its (nonzero) digits is 453600, while the sum is 42.
The spelling of 5210030674365 in words is "five trillion, two hundred ten billion, thirty million, six hundred seventy-four thousand, three hundred sixty-five".
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