Base | Representation |
---|---|
bin | 1111001010011100100… |
… | …01000100101011000101 |
3 | 1211210210200012122100001 |
4 | 13211032101010223011 |
5 | 32014004030010003 |
6 | 1035202422521301 |
7 | 52432653062641 |
oct | 7451621045305 |
9 | 1753720178301 |
10 | 521004141253 |
11 | 190a58289722 |
12 | 84b83296231 |
13 | 3a19088281b |
14 | 1b306a13c21 |
15 | d844aec61d |
hex | 794e444ac5 |
521004141253 has 2 divisors, whose sum is σ = 521004141254. Its totient is φ = 521004141252.
The previous prime is 521004141209. The next prime is 521004141299. The reversal of 521004141253 is 352141400125.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 329771102049 + 191233039204 = 574257^2 + 437302^2 .
It is a cyclic number.
It is not a de Polignac number, because 521004141253 - 213 = 521004133061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (521004151253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 260502070626 + 260502070627.
It is an arithmetic number, because the mean of its divisors is an integer number (260502070627).
Almost surely, 2521004141253 is an apocalyptic number.
It is an amenable number.
521004141253 is a deficient number, since it is larger than the sum of its proper divisors (1).
521004141253 is an equidigital number, since it uses as much as digits as its factorization.
521004141253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 521004141253 its reverse (352141400125), we get a palindrome (873145541378).
The spelling of 521004141253 in words is "five hundred twenty-one billion, four million, one hundred forty-one thousand, two hundred fifty-three".
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