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52104040133 is a prime number
BaseRepresentation
bin110000100001101001…
…001000111011000101
311222111012221111002012
4300201221020323011
51323202113241013
635534122224005
73523121014355
oct604151107305
9158435844065
1052104040133
11201084105a2
12a121655005
134bb49437a2
142743d4cb65
15154e4591a8
hexc21a48ec5

52104040133 has 2 divisors, whose sum is σ = 52104040134. Its totient is φ = 52104040132.

The previous prime is 52104040111. The next prime is 52104040181. The reversal of 52104040133 is 33104040125.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 37288768609 + 14815271524 = 193103^2 + 121718^2 .

It is a cyclic number.

It is not a de Polignac number, because 52104040133 - 28 = 52104039877 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 52104040099 and 52104040108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52104040033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26052020066 + 26052020067.

It is an arithmetic number, because the mean of its divisors is an integer number (26052020067).

Almost surely, 252104040133 is an apocalyptic number.

It is an amenable number.

52104040133 is a deficient number, since it is larger than the sum of its proper divisors (1).

52104040133 is an equidigital number, since it uses as much as digits as its factorization.

52104040133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 52104040133 its reverse (33104040125), we get a palindrome (85208080258).

The spelling of 52104040133 in words is "fifty-two billion, one hundred four million, forty thousand, one hundred thirty-three".