Base | Representation |
---|---|
bin | 1100011011010… |
… | …0101101110001 |
3 | 10122001222210102 |
4 | 3012310231301 |
5 | 101320323213 |
6 | 5101042145 |
7 | 1202005421 |
oct | 306645561 |
9 | 118058712 |
10 | 52120433 |
11 | 27469942 |
12 | 15556355 |
13 | aa4b5c1 |
14 | 6cca481 |
15 | 4898158 |
hex | 31b4b71 |
52120433 has 2 divisors, whose sum is σ = 52120434. Its totient is φ = 52120432.
The previous prime is 52120427. The next prime is 52120451. The reversal of 52120433 is 33402125.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52085089 + 35344 = 7217^2 + 188^2 .
It is a cyclic number.
It is not a de Polignac number, because 52120433 - 214 = 52104049 is a prime.
It is a super-2 number, since 2×521204332 = 5433079072214978, which contains 22 as substring.
It is a Sophie Germain prime.
It is a Chen prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (52120463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26060216 + 26060217.
It is an arithmetic number, because the mean of its divisors is an integer number (26060217).
Almost surely, 252120433 is an apocalyptic number.
It is an amenable number.
52120433 is a deficient number, since it is larger than the sum of its proper divisors (1).
52120433 is an equidigital number, since it uses as much as digits as its factorization.
52120433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 20.
The square root of 52120433 is about 7219.4482476156. The cubic root of 52120433 is about 373.5390457661.
Adding to 52120433 its reverse (33402125), we get a palindrome (85522558).
The spelling of 52120433 in words is "fifty-two million, one hundred twenty thousand, four hundred thirty-three".
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