Base | Representation |
---|---|
bin | 1111001010111010010… |
… | …00010110100011011111 |
3 | 1211211110001110001122221 |
4 | 13211131020112203133 |
5 | 32020011344412224 |
6 | 1035243251450211 |
7 | 52442101521361 |
oct | 7453510264337 |
9 | 1754401401587 |
10 | 521253513439 |
11 | 19107602373a |
12 | 850328b6967 |
13 | 3a200435529 |
14 | 1b32bba8d31 |
15 | d85b95a6e4 |
hex | 795d2168df |
521253513439 has 2 divisors, whose sum is σ = 521253513440. Its totient is φ = 521253513438.
The previous prime is 521253513413. The next prime is 521253513527. The reversal of 521253513439 is 934315352125.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-521253513439 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 521253513395 and 521253513404.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (521253513839) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 260626756719 + 260626756720.
It is an arithmetic number, because the mean of its divisors is an integer number (260626756720).
Almost surely, 2521253513439 is an apocalyptic number.
521253513439 is a deficient number, since it is larger than the sum of its proper divisors (1).
521253513439 is an equidigital number, since it uses as much as digits as its factorization.
521253513439 is an evil number, because the sum of its binary digits is even.
The product of its digits is 486000, while the sum is 43.
The spelling of 521253513439 in words is "five hundred twenty-one billion, two hundred fifty-three million, five hundred thirteen thousand, four hundred thirty-nine".
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