Base | Representation |
---|---|
bin | 100101111011011111111… |
… | …0111111010010010111011 |
3 | 200110100200221100121110211 |
4 | 1023312333313322102323 |
5 | 1140402223143410003 |
6 | 15030454211051551 |
7 | 1045425233404264 |
oct | 113667767722273 |
9 | 20410627317424 |
10 | 5213014435003 |
11 | 172a910822371 |
12 | 702397ba0bb7 |
13 | 2ba77b76a54b |
14 | 1404500ad96b |
15 | 909084e996d |
hex | 4bdbfdfa4bb |
5213014435003 has 2 divisors, whose sum is σ = 5213014435004. Its totient is φ = 5213014435002.
The previous prime is 5213014435001. The next prime is 5213014435009. The reversal of 5213014435003 is 3005344103125.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5213014435003 - 21 = 5213014435001 is a prime.
It is a super-2 number, since 2×52130144350032 (a number of 26 digits) contains 22 as substring.
Together with 5213014435001, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (5213014435001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2606507217501 + 2606507217502.
It is an arithmetic number, because the mean of its divisors is an integer number (2606507217502).
Almost surely, 25213014435003 is an apocalyptic number.
5213014435003 is a deficient number, since it is larger than the sum of its proper divisors (1).
5213014435003 is an equidigital number, since it uses as much as digits as its factorization.
5213014435003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 5213014435003 its reverse (3005344103125), we get a palindrome (8218358538128).
The spelling of 5213014435003 in words is "five trillion, two hundred thirteen billion, fourteen million, four hundred thirty-five thousand, three".
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