Base | Representation |
---|---|
bin | 1111001011000010001… |
… | …11100000100111111011 |
3 | 1211211121201022022200221 |
4 | 13211201013200213323 |
5 | 32020131010321103 |
6 | 1035254041240511 |
7 | 52443543204124 |
oct | 7454107404773 |
9 | 1754551268627 |
10 | 521320401403 |
11 | 1910aa85964a |
12 | 85051193137 |
13 | 3a2112546c9 |
14 | 1b336a1b04b |
15 | d86276e1bd |
hex | 79611e09fb |
521320401403 has 2 divisors, whose sum is σ = 521320401404. Its totient is φ = 521320401402.
The previous prime is 521320401391. The next prime is 521320401449. The reversal of 521320401403 is 304104023125.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 521320401403 - 29 = 521320400891 is a prime.
It is not a weakly prime, because it can be changed into another prime (521320407403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 260660200701 + 260660200702.
It is an arithmetic number, because the mean of its divisors is an integer number (260660200702).
Almost surely, 2521320401403 is an apocalyptic number.
521320401403 is a deficient number, since it is larger than the sum of its proper divisors (1).
521320401403 is an equidigital number, since it uses as much as digits as its factorization.
521320401403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 521320401403 its reverse (304104023125), we get a palindrome (825424424528).
The spelling of 521320401403 in words is "five hundred twenty-one billion, three hundred twenty million, four hundred one thousand, four hundred three".
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