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52140131 is a prime number
BaseRepresentation
bin1100011011100…
…1100001100011
310122002222210222
43012321201203
5101321441011
65101313255
71202120021
oct306714143
9118088728
1052140131
112748271a
121556582b
13aa57564
146cd3711
15489dddb
hex31b9863

52140131 has 2 divisors, whose sum is σ = 52140132. Its totient is φ = 52140130.

The previous prime is 52140097. The next prime is 52140133. The reversal of 52140131 is 13104125.

52140131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 52140131 - 210 = 52139107 is a prime.

It is a super-2 number, since 2×521401312 = 5437186521394322, which contains 22 as substring.

Together with 52140133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (52140133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26070065 + 26070066.

It is an arithmetic number, because the mean of its divisors is an integer number (26070066).

Almost surely, 252140131 is an apocalyptic number.

52140131 is a deficient number, since it is larger than the sum of its proper divisors (1).

52140131 is an equidigital number, since it uses as much as digits as its factorization.

52140131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 52140131 is about 7220.8123504215. The cubic root of 52140131 is about 373.5860973410.

Adding to 52140131 its reverse (13104125), we get a palindrome (65244256).

The spelling of 52140131 in words is "fifty-two million, one hundred forty thousand, one hundred thirty-one".