Search a number
-
+
5214749984640 = 273857315997
BaseRepresentation
bin100101111100010011101…
…0100100000011110000000
3200110112011220002200000000
41023320213110200132000
51140414301444002030
615031342330000000
71045516236340620
oct113704724403600
920415156080000
105214749984640
111730621466509
127027a1276000
132ba9971b2ab1
141405767aa880
15909aaa71860
hex4be27520780

5214749984640 has 2304 divisors, whose sum is σ = 22664594534400. Its totient is φ = 1122252226560.

The previous prime is 5214749984629. The next prime is 5214749984659. The reversal of 5214749984640 is 464899474125.

5214749984640 is a `hidden beast` number, since 5 + 2 + 1 + 4 + 7 + 499 + 84 + 64 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (63).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 53760309072 + ... + 53760309168.

It is an arithmetic number, because the mean of its divisors is an integer number (9837063600).

Almost surely, 25214749984640 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 5214749984640, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (11332297267200).

5214749984640 is an abundant number, since it is smaller than the sum of its proper divisors (17449844549760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

5214749984640 is an frugal number, since it uses more digits than its factorization.

5214749984640 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 237 (or 204 counting only the distinct ones).

The product of its (nonzero) digits is 69672960, while the sum is 63.

The spelling of 5214749984640 in words is "five trillion, two hundred fourteen billion, seven hundred forty-nine million, nine hundred eighty-four thousand, six hundred forty".