Base | Representation |
---|---|
bin | 110000100100101110… |
… | …001011000100100111 |
3 | 11222121211010122011111 |
4 | 300210232023010213 |
5 | 1323303324110203 |
6 | 35543205245451 |
7 | 3524316030022 |
oct | 604456130447 |
9 | 158554118144 |
10 | 52155691303 |
11 | 20134589911 |
12 | a136a03887 |
13 | 4bc2559601 |
14 | 274ab561b9 |
15 | 1553c5d26d |
hex | c24b8b127 |
52155691303 has 2 divisors, whose sum is σ = 52155691304. Its totient is φ = 52155691302.
The previous prime is 52155691213. The next prime is 52155691409. The reversal of 52155691303 is 30319655125.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 52155691303 - 229 = 51618820391 is a prime.
It is a super-2 number, since 2×521556913032 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52155694303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26077845651 + 26077845652.
It is an arithmetic number, because the mean of its divisors is an integer number (26077845652).
Almost surely, 252155691303 is an apocalyptic number.
52155691303 is a deficient number, since it is larger than the sum of its proper divisors (1).
52155691303 is an equidigital number, since it uses as much as digits as its factorization.
52155691303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 121500, while the sum is 40.
The spelling of 52155691303 in words is "fifty-two billion, one hundred fifty-five million, six hundred ninety-one thousand, three hundred three".
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