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5221125040035 = 351720475000157
BaseRepresentation
bin100101111111010001101…
…0011011010011110100011
3200111010122011220000221210
41023332203103122132203
51141020331002240120
615034315101321203
71046133226406142
oct113764323323643
920433564800853
105221125040035
1117332a2a74a33
12703a80266203
132bb471b98218
141409bd329759
1590c30591ce0
hex4bfa34da7a3

5221125040035 has 16 divisors (see below), whose sum is σ = 8845200068256. Its totient is φ = 2620800019968.

The previous prime is 5221125039959. The next prime is 5221125040049. The reversal of 5221125040035 is 5300405211225.

It is not a de Polignac number, because 5221125040035 - 212 = 5221125035939 is a prime.

It is a super-3 number, since 3×52211250400353 (a number of 39 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5221125039984 and 5221125040011.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10237499824 + ... + 10237500333.

It is an arithmetic number, because the mean of its divisors is an integer number (552825004266).

Almost surely, 25221125040035 is an apocalyptic number.

5221125040035 is a deficient number, since it is larger than the sum of its proper divisors (3624075028221).

5221125040035 is a wasteful number, since it uses less digits than its factorization.

5221125040035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20475000182.

The product of its (nonzero) digits is 12000, while the sum is 30.

The spelling of 5221125040035 in words is "five trillion, two hundred twenty-one billion, one hundred twenty-five million, forty thousand, thirty-five".

Divisors: 1 3 5 15 17 51 85 255 20475000157 61425000471 102375000785 307125002355 348075002669 1044225008007 1740375013345 5221125040035