Base | Representation |
---|---|
bin | 100101111111010001101… |
… | …0011011010011110100011 |
3 | 200111010122011220000221210 |
4 | 1023332203103122132203 |
5 | 1141020331002240120 |
6 | 15034315101321203 |
7 | 1046133226406142 |
oct | 113764323323643 |
9 | 20433564800853 |
10 | 5221125040035 |
11 | 17332a2a74a33 |
12 | 703a80266203 |
13 | 2bb471b98218 |
14 | 1409bd329759 |
15 | 90c30591ce0 |
hex | 4bfa34da7a3 |
5221125040035 has 16 divisors (see below), whose sum is σ = 8845200068256. Its totient is φ = 2620800019968.
The previous prime is 5221125039959. The next prime is 5221125040049. The reversal of 5221125040035 is 5300405211225.
It is not a de Polignac number, because 5221125040035 - 212 = 5221125035939 is a prime.
It is a super-3 number, since 3×52211250400353 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5221125039984 and 5221125040011.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10237499824 + ... + 10237500333.
It is an arithmetic number, because the mean of its divisors is an integer number (552825004266).
Almost surely, 25221125040035 is an apocalyptic number.
5221125040035 is a deficient number, since it is larger than the sum of its proper divisors (3624075028221).
5221125040035 is a wasteful number, since it uses less digits than its factorization.
5221125040035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20475000182.
The product of its (nonzero) digits is 12000, while the sum is 30.
The spelling of 5221125040035 in words is "five trillion, two hundred twenty-one billion, one hundred twenty-five million, forty thousand, thirty-five".
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