Base | Representation |
---|---|
bin | 100101111111010001101… |
… | …0011011010011101010111 |
3 | 200111010122011220000211222 |
4 | 1023332203103122131113 |
5 | 1141020331002234314 |
6 | 15034315101320555 |
7 | 1046133226406003 |
oct | 113764323323527 |
9 | 20433564800758 |
10 | 5221125039959 |
11 | 17332a2a74974 |
12 | 703a8026615b |
13 | 2bb471b9818a |
14 | 1409bd329703 |
15 | 90c30591c8e |
hex | 4bfa34da757 |
5221125039959 has 2 divisors, whose sum is σ = 5221125039960. Its totient is φ = 5221125039958.
The previous prime is 5221125039953. The next prime is 5221125040049. The reversal of 5221125039959 is 9599305211225.
5221125039959 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5221125039959 - 28 = 5221125039703 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5221125039959.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5221125039953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2610562519979 + 2610562519980.
It is an arithmetic number, because the mean of its divisors is an integer number (2610562519980).
Almost surely, 25221125039959 is an apocalyptic number.
5221125039959 is a deficient number, since it is larger than the sum of its proper divisors (1).
5221125039959 is an equidigital number, since it uses as much as digits as its factorization.
5221125039959 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2187000, while the sum is 53.
The spelling of 5221125039959 in words is "five trillion, two hundred twenty-one billion, one hundred twenty-five million, thirty-nine thousand, nine hundred fifty-nine".
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