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5221125039959 is a prime number
BaseRepresentation
bin100101111111010001101…
…0011011010011101010111
3200111010122011220000211222
41023332203103122131113
51141020331002234314
615034315101320555
71046133226406003
oct113764323323527
920433564800758
105221125039959
1117332a2a74974
12703a8026615b
132bb471b9818a
141409bd329703
1590c30591c8e
hex4bfa34da757

5221125039959 has 2 divisors, whose sum is σ = 5221125039960. Its totient is φ = 5221125039958.

The previous prime is 5221125039953. The next prime is 5221125040049. The reversal of 5221125039959 is 9599305211225.

5221125039959 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5221125039959 - 28 = 5221125039703 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5221125039959.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5221125039953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2610562519979 + 2610562519980.

It is an arithmetic number, because the mean of its divisors is an integer number (2610562519980).

Almost surely, 25221125039959 is an apocalyptic number.

5221125039959 is a deficient number, since it is larger than the sum of its proper divisors (1).

5221125039959 is an equidigital number, since it uses as much as digits as its factorization.

5221125039959 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2187000, while the sum is 53.

The spelling of 5221125039959 in words is "five trillion, two hundred twenty-one billion, one hundred twenty-five million, thirty-nine thousand, nine hundred fifty-nine".