Base | Representation |
---|---|
bin | 100101111111010001101… |
… | …0011011010011110110011 |
3 | 200111010122011220000222101 |
4 | 1023332203103122132303 |
5 | 1141020331002240201 |
6 | 15034315101321231 |
7 | 1046133226406164 |
oct | 113764323323663 |
9 | 20433564800871 |
10 | 5221125040051 |
11 | 17332a2a74a48 |
12 | 703a80266217 |
13 | 2bb471b9822b |
14 | 1409bd32976b |
15 | 90c30591d01 |
hex | 4bfa34da7b3 |
5221125040051 has 2 divisors, whose sum is σ = 5221125040052. Its totient is φ = 5221125040050.
The previous prime is 5221125040049. The next prime is 5221125040081. The reversal of 5221125040051 is 1500405211225.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5221125040051 - 21 = 5221125040049 is a prime.
It is a super-3 number, since 3×52211250400513 (a number of 39 digits) contains 333 as substring.
Together with 5221125040049, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (5221125040081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2610562520025 + 2610562520026.
It is an arithmetic number, because the mean of its divisors is an integer number (2610562520026).
Almost surely, 25221125040051 is an apocalyptic number.
5221125040051 is a deficient number, since it is larger than the sum of its proper divisors (1).
5221125040051 is an equidigital number, since it uses as much as digits as its factorization.
5221125040051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4000, while the sum is 28.
The spelling of 5221125040051 in words is "five trillion, two hundred twenty-one billion, one hundred twenty-five million, forty thousand, fifty-one".
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