Base | Representation |
---|---|
bin | 10111110000001111011110… |
… | …10100011111110101000101 |
3 | 20211221121221210111021021212 |
4 | 23320013233110133311011 |
5 | 23321310002234231113 |
6 | 303032251313221205 |
7 | 14000601531445526 |
oct | 1370075724376505 |
9 | 224847853437255 |
10 | 52235112414533 |
11 | 15709872211884 |
12 | 5a37621561805 |
13 | 231b999899559 |
14 | cc829b58884d |
15 | 608b4d94a0a8 |
hex | 2f81ef51fd45 |
52235112414533 has 2 divisors, whose sum is σ = 52235112414534. Its totient is φ = 52235112414532.
The previous prime is 52235112414509. The next prime is 52235112414539. The reversal of 52235112414533 is 33541421153225.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49521719385889 + 2713393028644 = 7037167^2 + 1647238^2 .
It is a cyclic number.
It is not a de Polignac number, because 52235112414533 - 214 = 52235112398149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52235112414539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26117556207266 + 26117556207267.
It is an arithmetic number, because the mean of its divisors is an integer number (26117556207267).
Almost surely, 252235112414533 is an apocalyptic number.
It is an amenable number.
52235112414533 is a deficient number, since it is larger than the sum of its proper divisors (1).
52235112414533 is an equidigital number, since it uses as much as digits as its factorization.
52235112414533 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 432000, while the sum is 41.
Adding to 52235112414533 its reverse (33541421153225), we get a palindrome (85776533567758).
The spelling of 52235112414533 in words is "fifty-two trillion, two hundred thirty-five billion, one hundred twelve million, four hundred fourteen thousand, five hundred thirty-three".
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