Base | Representation |
---|---|
bin | 110000101011010001… |
… | …011111101010110011 |
3 | 11222220110222021202121 |
4 | 300223101133222303 |
5 | 1324014444122003 |
6 | 40002133255111 |
7 | 3530122250251 |
oct | 605321375263 |
9 | 158813867677 |
10 | 52265614003 |
11 | 20190638419 |
12 | a167794497 |
13 | 4c0c265725 |
14 | 275b5ab5d1 |
15 | 155d722cbd |
hex | c2b45fab3 |
52265614003 has 2 divisors, whose sum is σ = 52265614004. Its totient is φ = 52265614002.
The previous prime is 52265613937. The next prime is 52265614021. The reversal of 52265614003 is 30041656225.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 52265614003 - 225 = 52232059571 is a prime.
It is a super-2 number, since 2×522656140032 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 52265614003.
It is not a weakly prime, because it can be changed into another prime (52265614103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26132807001 + 26132807002.
It is an arithmetic number, because the mean of its divisors is an integer number (26132807002).
Almost surely, 252265614003 is an apocalyptic number.
52265614003 is a deficient number, since it is larger than the sum of its proper divisors (1).
52265614003 is an equidigital number, since it uses as much as digits as its factorization.
52265614003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 34.
The spelling of 52265614003 in words is "fifty-two billion, two hundred sixty-five million, six hundred fourteen thousand, three".
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