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5229125743 is a prime number
BaseRepresentation
bin1001101111010111…
…00010000001101111
3111111102112002222211
410313223202001233
541202124010433
62222514151251
7243403556362
oct46753420157
914442462884
105229125743
112243783626
12101b282527
13654472c5a
143786a60d9
152091158cd
hex137ae206f

5229125743 has 2 divisors, whose sum is σ = 5229125744. Its totient is φ = 5229125742.

The previous prime is 5229125723. The next prime is 5229125777. The reversal of 5229125743 is 3475219225.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5229125743 - 25 = 5229125711 is a prime.

It is a super-2 number, since 2×52291257432 = 54687512072210604098, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5229125696 and 5229125705.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5229125723) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2614562871 + 2614562872.

It is an arithmetic number, because the mean of its divisors is an integer number (2614562872).

Almost surely, 25229125743 is an apocalyptic number.

5229125743 is a deficient number, since it is larger than the sum of its proper divisors (1).

5229125743 is an equidigital number, since it uses as much as digits as its factorization.

5229125743 is an evil number, because the sum of its binary digits is even.

The product of its digits is 151200, while the sum is 40.

The square root of 5229125743 is about 72312.6942037150. The cubic root of 5229125743 is about 1735.7067874214.

The spelling of 5229125743 in words is "five billion, two hundred twenty-nine million, one hundred twenty-five thousand, seven hundred forty-three".