Base | Representation |
---|---|
bin | 10111110010001110111001… |
… | …11000011000010000010101 |
3 | 20212012011112102012020001011 |
4 | 23321013130320120100111 |
5 | 23323420103231432300 |
6 | 303123523451332221 |
7 | 14005543022026333 |
oct | 1371073470302025 |
9 | 225164472166034 |
10 | 52303522530325 |
11 | 15735887a11360 |
12 | 5a48933a51071 |
13 | 232527c810601 |
14 | ccb70ad80b53 |
15 | 60a8046a8eba |
hex | 2f91dce18415 |
52303522530325 has 48 divisors (see below), whose sum is σ = 73308140300160. Its totient is φ = 36669030048000.
The previous prime is 52303522530227. The next prime is 52303522530353.
52303522530325 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 52303522530325 - 237 = 52166083576853 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 164634 + ... + 10229083.
It is an arithmetic number, because the mean of its divisors is an integer number (1527252922920).
Almost surely, 252303522530325 is an apocalyptic number.
52303522530325 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
52303522530325 is a deficient number, since it is larger than the sum of its proper divisors (21004617769835).
52303522530325 is a wasteful number, since it uses less digits than its factorization.
52303522530325 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10394398 (or 10394393 counting only the distinct ones).
The product of its (nonzero) digits is 810000, while the sum is 40.
It can be divided in two parts, 5230352 and 2530325, that added together give a palindrome (7760677).
The spelling of 52303522530325 in words is "fifty-two trillion, three hundred three billion, five hundred twenty-two million, five hundred thirty thousand, three hundred twenty-five".
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