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52316324331053 is a prime number
BaseRepresentation
bin10111110010100110101111…
…11011010111111000101101
320212020101120121001002012212
423321103113323113320231
523324122313012043203
6303133442042340205
714006505200366456
oct1371232773277055
9225211517032185
1052316324331053
1115740257223762
125a4b3071ba665
13232653cb08823
14ccc1a327612d
1560ad0350a1d8
hex2f94d7ed7e2d

52316324331053 has 2 divisors, whose sum is σ = 52316324331054. Its totient is φ = 52316324331052.

The previous prime is 52316324330993. The next prime is 52316324331059. The reversal of 52316324331053 is 35013342361325.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 46147593412804 + 6168730918249 = 6793202^2 + 2483693^2 .

It is a cyclic number.

It is not a de Polignac number, because 52316324331053 - 218 = 52316324068909 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 52316324331053.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52316324331059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26158162165526 + 26158162165527.

It is an arithmetic number, because the mean of its divisors is an integer number (26158162165527).

Almost surely, 252316324331053 is an apocalyptic number.

It is an amenable number.

52316324331053 is a deficient number, since it is larger than the sum of its proper divisors (1).

52316324331053 is an equidigital number, since it uses as much as digits as its factorization.

52316324331053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 583200, while the sum is 41.

Adding to 52316324331053 its reverse (35013342361325), we get a palindrome (87329666692378).

The spelling of 52316324331053 in words is "fifty-two trillion, three hundred sixteen billion, three hundred twenty-four million, three hundred thirty-one thousand, fifty-three".