Base | Representation |
---|---|
bin | 100110000100100101100… |
… | …1110110100010011011001 |
3 | 200112020002011202000102022 |
4 | 1030021023032310103121 |
5 | 1141212211234420402 |
6 | 15043443035344225 |
7 | 1050016013025203 |
oct | 114111316642331 |
9 | 20466064660368 |
10 | 5232532341977 |
11 | 17381171057a6 |
12 | 7061245b2075 |
13 | 2bc56c2bc925 |
14 | 141382341773 |
15 | 9119bc882a2 |
hex | 4c24b3b44d9 |
5232532341977 has 2 divisors, whose sum is σ = 5232532341978. Its totient is φ = 5232532341976.
The previous prime is 5232532341961. The next prime is 5232532341983. The reversal of 5232532341977 is 7791432352325.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4109941235401 + 1122591106576 = 2027299^2 + 1059524^2 .
It is a cyclic number.
It is not a de Polignac number, because 5232532341977 - 24 = 5232532341961 is a prime.
It is not a weakly prime, because it can be changed into another prime (5232532341577) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2616266170988 + 2616266170989.
It is an arithmetic number, because the mean of its divisors is an integer number (2616266170989).
Almost surely, 25232532341977 is an apocalyptic number.
It is an amenable number.
5232532341977 is a deficient number, since it is larger than the sum of its proper divisors (1).
5232532341977 is an equidigital number, since it uses as much as digits as its factorization.
5232532341977 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9525600, while the sum is 53.
The spelling of 5232532341977 in words is "five trillion, two hundred thirty-two billion, five hundred thirty-two million, three hundred forty-one thousand, nine hundred seventy-seven".
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