Base | Representation |
---|---|
bin | 100110000100110011111… |
… | …1100010110011111110001 |
3 | 200112021022202010211122121 |
4 | 1030021213330112133301 |
5 | 1141214203043244221 |
6 | 15044002524034241 |
7 | 1050033652266226 |
oct | 114114774263761 |
9 | 20467282124577 |
10 | 5233014040561 |
11 | 1738344001aaa |
12 | 706239992981 |
13 | 2bc618037788 |
14 | 1413ca2d194d |
15 | 911c91d8a41 |
hex | 4c267f167f1 |
5233014040561 has 2 divisors, whose sum is σ = 5233014040562. Its totient is φ = 5233014040560.
The previous prime is 5233014040543. The next prime is 5233014040567. The reversal of 5233014040561 is 1650404103325.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5178605679025 + 54408361536 = 2275655^2 + 233256^2 .
It is a cyclic number.
It is not a de Polignac number, because 5233014040561 - 211 = 5233014038513 is a prime.
It is not a weakly prime, because it can be changed into another prime (5233014040567) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2616507020280 + 2616507020281.
It is an arithmetic number, because the mean of its divisors is an integer number (2616507020281).
Almost surely, 25233014040561 is an apocalyptic number.
It is an amenable number.
5233014040561 is a deficient number, since it is larger than the sum of its proper divisors (1).
5233014040561 is an equidigital number, since it uses as much as digits as its factorization.
5233014040561 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 5233014040561 its reverse (1650404103325), we get a palindrome (6883418143886).
The spelling of 5233014040561 in words is "five trillion, two hundred thirty-three billion, fourteen million, forty thousand, five hundred sixty-one".
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