Base | Representation |
---|---|
bin | 100110000101010001111… |
… | …1010100011111100100101 |
3 | 200112100220212102020212012 |
4 | 1030022203322203330211 |
5 | 1141223233133014300 |
6 | 15044250425404005 |
7 | 1050100620451253 |
oct | 114124372437445 |
9 | 20470825366765 |
10 | 5234020204325 |
11 | 173880aa55800 |
12 | 70647a939605 |
13 | 2bc748622353 |
14 | 141483ba55d3 |
15 | 912376d6435 |
hex | 4c2a3ea3f25 |
5234020204325 has 72 divisors (see below), whose sum is σ = 7180907059200. Its totient is φ = 3781520265600.
The previous prime is 5234020204307. The next prime is 5234020204339.
5234020204325 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 5234020204325 - 226 = 5233953095461 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5234020204291 and 5234020204300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 320723516 + ... + 320739834.
Almost surely, 25234020204325 is an apocalyptic number.
5234020204325 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
5234020204325 is a deficient number, since it is larger than the sum of its proper divisors (1946886854875).
5234020204325 is a wasteful number, since it uses less digits than its factorization.
5234020204325 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17043 (or 17027 counting only the distinct ones).
The product of its (nonzero) digits is 57600, while the sum is 32.
It can be divided in two parts, 5234020 and 204325, that added together give a palindrome (5438345).
The spelling of 5234020204325 in words is "five trillion, two hundred thirty-four billion, twenty million, two hundred four thousand, three hundred twenty-five".
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