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52341335504000 = 27535399761909
BaseRepresentation
bin10111110011010101010101…
…01101011011010010000000
320212022210010122222022102122
423321222222231123102000
523330030023342112000
6303153135542503412
714011352042014154
oct1371525255332200
9225283118868378
1052341335504000
111574a9213a1124
125a54127434b68
1323289c775474a
14ccd496ccb064
1560b7b9188085
hex2f9aaab5b480

52341335504000 has 256 divisors, whose sum is σ = 132724128981600. Its totient is φ = 20520570470400.

The previous prime is 52341335503949. The next prime is 52341335504009. The reversal of 52341335504000 is 40553314325.

It is a happy number.

52341335504000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 16 ways, for example, as 7018387802176 + 45322947701824 = 2649224^2 + 6732232^2 .

It is not an unprimeable number, because it can be changed into a prime (52341335504009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 845425046 + ... + 845486954.

Almost surely, 252341335504000 is an apocalyptic number.

52341335504000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 52341335504000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (66362064490800).

52341335504000 is an abundant number, since it is smaller than the sum of its proper divisors (80382793477600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

52341335504000 is an equidigital number, since it uses as much as digits as its factorization.

52341335504000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62988 (or 62966 counting only the distinct ones).

The product of its (nonzero) digits is 108000, while the sum is 35.

Adding to 52341335504000 its reverse (40553314325), we get a palindrome (52381888818325).

The spelling of 52341335504000 in words is "fifty-two trillion, three hundred forty-one billion, three hundred thirty-five million, five hundred four thousand".