Base | Representation |
---|---|
bin | 110000110101010001… |
… | …101011001101100011 |
3 | 12000100011202101202102 |
4 | 300311101223031203 |
5 | 1324340424332233 |
6 | 40030530241015 |
7 | 3534230554616 |
oct | 606521531543 |
9 | 160304671672 |
10 | 52433433443 |
11 | 20267340676 |
12 | a1b3a2616b |
13 | 4c37c63381 |
14 | 27759b417d |
15 | 156d3221e8 |
hex | c3546b363 |
52433433443 has 2 divisors, whose sum is σ = 52433433444. Its totient is φ = 52433433442.
The previous prime is 52433433407. The next prime is 52433433509. The reversal of 52433433443 is 34433433425.
52433433443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 52433433443 - 218 = 52433171299 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 52433433397 and 52433433406.
It is not a weakly prime, because it can be changed into another prime (52433430443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26216716721 + 26216716722.
It is an arithmetic number, because the mean of its divisors is an integer number (26216716722).
Almost surely, 252433433443 is an apocalyptic number.
52433433443 is a deficient number, since it is larger than the sum of its proper divisors (1).
52433433443 is an equidigital number, since it uses as much as digits as its factorization.
52433433443 is an evil number, because the sum of its binary digits is even.
The product of its digits is 622080, while the sum is 38.
Adding to 52433433443 its reverse (34433433425), we get a palindrome (86866866868).
The spelling of 52433433443 in words is "fifty-two billion, four hundred thirty-three million, four hundred thirty-three thousand, four hundred forty-three".
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