Base | Representation |
---|---|
bin | 10111110110000010101101… |
… | …00000001000111000101111 |
3 | 20212122200101022211222110102 |
4 | 23323001112200020320233 |
5 | 23333041133433441101 |
6 | 303304011503301315 |
7 | 14021155416216035 |
oct | 1373012640107057 |
9 | 225580338758412 |
10 | 52434412015151 |
11 | 15786344690611 |
12 | 5a6a1825aa83b |
13 | 233470ba6960a |
14 | cd3ba662a555 |
15 | 60de1566d86b |
hex | 2fb056808e2f |
52434412015151 has 32 divisors (see below), whose sum is σ = 56297748971520. Its totient is φ = 48728213820000.
The previous prime is 52434412015147. The next prime is 52434412015199. The reversal of 52434412015151 is 15151021443425.
It is a cyclic number.
It is not a de Polignac number, because 52434412015151 - 22 = 52434412015147 is a prime.
It is a super-3 number, since 3×524344120151513 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52434412015121) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 37160966 + ... + 38546156.
It is an arithmetic number, because the mean of its divisors is an integer number (1759304655360).
Almost surely, 252434412015151 is an apocalyptic number.
52434412015151 is a deficient number, since it is larger than the sum of its proper divisors (3863336956369).
52434412015151 is a wasteful number, since it uses less digits than its factorization.
52434412015151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1385627.
The product of its (nonzero) digits is 96000, while the sum is 38.
Adding to 52434412015151 its reverse (15151021443425), we get a palindrome (67585433458576).
The spelling of 52434412015151 in words is "fifty-two trillion, four hundred thirty-four billion, four hundred twelve million, fifteen thousand, one hundred fifty-one".
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