Base | Representation |
---|---|
bin | 110000110110010010… |
… | …001000101100010101 |
3 | 12000101100112220102011 |
4 | 300312102020230111 |
5 | 1324404241101123 |
6 | 40032332344221 |
7 | 3534524314054 |
oct | 606622105425 |
9 | 160340486364 |
10 | 52450331413 |
11 | 20275932337 |
12 | a1b9615071 |
13 | 4c3b5cb87c |
14 | 2777d3239b |
15 | 156ea5de0d |
hex | c36488b15 |
52450331413 has 2 divisors, whose sum is σ = 52450331414. Its totient is φ = 52450331412.
The previous prime is 52450331377. The next prime is 52450331431. The reversal of 52450331413 is 31413305425.
Together with next prime (52450331431) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 46803860964 + 5646470449 = 216342^2 + 75143^2 .
It is a cyclic number.
It is not a de Polignac number, because 52450331413 - 29 = 52450330901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52450332413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26225165706 + 26225165707.
It is an arithmetic number, because the mean of its divisors is an integer number (26225165707).
Almost surely, 252450331413 is an apocalyptic number.
It is an amenable number.
52450331413 is a deficient number, since it is larger than the sum of its proper divisors (1).
52450331413 is an equidigital number, since it uses as much as digits as its factorization.
52450331413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 52450331413 its reverse (31413305425), we get a palindrome (83863636838).
The spelling of 52450331413 in words is "fifty-two billion, four hundred fifty million, three hundred thirty-one thousand, four hundred thirteen".
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